Two wires are vibrating together to produce 10 beats/sec. Frequency of one wire is 200Hz. When tension in this wire is increased beat frequency remains unchanged. Frequency (in Hz) of other wire minus 206 Hz is equal to.
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Ans. 4
Sol. Frequency of first wire is less than that of second wire as upon increasing tension beats frequency remains unchanged.
∴ ν = ν 1 + 10 = 210 Hz
∴ ν – 206 = 4
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